A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction coefficient between the block and the surface is `mu`. Maximum velocity of the block will be

Explanation

Power`" "` P=F.v=constant
`F=(P)/(v) " or "Fprop(1)/(v)`
as v increases, F decreases.
when `F=mumg`, net force on block becomes zero, i.e., it has maximum or terminal velocity
`:. P=(mumg)v_(max) " or " v_(max) " or " v_(max)=(P)/(mumg)`