Home
Class 11
PHYSICS
The potential energy of a particle of ma...

The potential energy of a particle of mass 1 kg `U = 10 + (x-2)^(2)`. Here, U is in joule and x in meter. On the positive x=axis particle travels up to x=+6cm. Choose the wrong statement.

A

On negative X-axis particle travels upto x=-2 m

B

The maximum kinetic energy of the particle is 16 J

C

Both (a) and (b) are correct

D

Both (a) and (b) are incorrect

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the potential energy function given and determine the statements about the particle's motion. Let's break it down step by step. ### Step 1: Understand the potential energy function The potential energy \( U \) of the particle is given by: \[ U = 10 + (x - 2)^2 \] where \( U \) is in joules and \( x \) is in meters. ### Step 2: Convert the position to meters The particle travels up to \( x = 6 \) cm. We need to convert this to meters: \[ x = 6 \, \text{cm} = 0.06 \, \text{m} \] ### Step 3: Calculate the potential energy at \( x = 0.06 \, \text{m} \) Substituting \( x = 0.06 \) into the potential energy function: \[ U = 10 + (0.06 - 2)^2 \] Calculating \( 0.06 - 2 \): \[ 0.06 - 2 = -1.94 \] Now squaring this value: \[ (-1.94)^2 = 3.7616 \] Now substituting back into the potential energy equation: \[ U = 10 + 3.7616 = 13.7616 \, \text{J} \] ### Step 4: Find the minimum potential energy The potential energy is minimum when \( x = 2 \) m. Let's calculate \( U \) at this position: \[ U = 10 + (2 - 2)^2 = 10 + 0 = 10 \, \text{J} \] ### Step 5: Calculate the maximum potential energy The maximum potential energy occurs at the extreme position \( x = 6 \, \text{cm} \): \[ U = 10 + (0.06 - 2)^2 = 13.7616 \, \text{J} \] ### Step 6: Total mechanical energy The total mechanical energy \( E \) of the system is equal to the potential energy at the maximum position: \[ E = U_{\text{max}} = 13.7616 \, \text{J} \] ### Step 7: Calculate maximum kinetic energy The maximum kinetic energy \( K_{\text{max}} \) can be calculated using the conservation of energy: \[ K_{\text{max}} = E - U_{\text{min}} = 13.7616 \, \text{J} - 10 \, \text{J} = 3.7616 \, \text{J} \] ### Step 8: Identify the wrong statement Now we need to evaluate the statements given in the problem. The wrong statement will be the one that contradicts our findings. ### Conclusion The calculations show that: - The potential energy at \( x = 6 \, \text{cm} \) is approximately \( 13.76 \, \text{J} \). - The minimum potential energy is \( 10 \, \text{J} \). - The maximum kinetic energy is approximately \( 3.76 \, \text{J} \). Thus, the wrong statement among the options provided would be one that does not align with these calculated values.

To solve the problem, we need to analyze the potential energy function given and determine the statements about the particle's motion. Let's break it down step by step. ### Step 1: Understand the potential energy function The potential energy \( U \) of the particle is given by: \[ U = 10 + (x - 2)^2 \] where \( U \) is in joules and \( x \) is in meters. ...
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    DC PANDEY ENGLISH|Exercise MEDICAL ENTRANCE SPECIAL QUESTIONS|16 Videos
  • WORK, ENERGY AND POWER

    DC PANDEY ENGLISH|Exercise MATCH THE COLUMNS|7 Videos
  • WORK, ENERGY AND POWER

    DC PANDEY ENGLISH|Exercise CHECK POINT 6.3|10 Videos
  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 2 Comprehension Based|2 Videos
  • WORK, POWER AND ENERGY

    DC PANDEY ENGLISH|Exercise E Integer Type Questions|11 Videos

Similar Questions

Explore conceptually related problems

The potential energy of a particle of mass 1 kg U = 10 + (x-2)^(2) . Herer, U is in joule and x in met. On the positive x=axis particle travels up to x=+6cm. Choose the wrong statement.

Potential energy of a particle in SHM along x - axis is gives by U = 10 + (x - 2)^(2) Here, U is in joule and x in metre. Total mechanical energy of the particle is 26 J . Mass of the particle is 2kg . Find (a) angular frequency of SHM, (b) potential energy and kinetic energy at mean position and extreme position, (c ) amplitude of oscillation, (d) x - coordinates between which particle oscillates.

potential enrgy of a particle along x-axis varies as, U=-20 + (x-2)^(2) , where U is in joule and x in meter. Find the equilibrium position and state whether it is stable or unstable equilibrium.

The potential energy of a particle oscillating along x-axis is given as U=20+(x-2)^(2) Here, U is in joules and x in meters. Total mechanical energy of the particle is 36J . (a) State whether the motion of the particle is simple harmonic or not. (b) Find the mean position. (c) Find the maximum kinetic energy of the particle.

Potential energy of a particle moving along x-axis is by U=(x^(3)/3-4x + 6) . here, U is in joule and x in metre. Find position of stable and unstable equilibrium.

The potential energy of a particle of mass 1 kg moving in X-Y plane is given by U=(12x+5y) joules, where x an y are in meters. If the particle is initially at rest at origin, then select incorrect alternative :-

athe potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at

The potential energy of a particle of mass 2 kg in SHM is (9x^(2)) J. Here x is the displacement from mean position . If total mechanical energy of the particle is 36 J. The maximum speed of the particle is

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that

The potential energy of a particle moving along y axis is given by U(y)= 3y^4+12y^2 ,(where U is in joule and y is in metre). If total mechanical energy is 15 joule, then limits of motion are

DC PANDEY ENGLISH-WORK, ENERGY AND POWER-EXERCISES(TAKING IT TOGETHER)
  1. The system shown in the figure is released from rest. At the instant w...

    Text Solution

    |

  2. A plank of mass 10 kg and a block of mass 2 kg are placed on a horizon...

    Text Solution

    |

  3. A block of mass 5 kg slides down a rough inclined surface. The angle o...

    Text Solution

    |

  4. A particle moves move on the rough horizontal ground with some initial...

    Text Solution

    |

  5. A 50 kg girl is swinging on a swing from rest. Then, the power deliver...

    Text Solution

    |

  6. A bead can slide on a smooth circular wire frame of radius r which is ...

    Text Solution

    |

  7. A uniform chain has a mass M and length L. It is placed on a frictionl...

    Text Solution

    |

  8. A particle of mass 1 g executes an oscillatory motion on the concave s...

    Text Solution

    |

  9. A mass-spring system oscillates such that the mass moves on a rough su...

    Text Solution

    |

  10. A uniform flexible chain of mass m and length l hangs in equilibrium o...

    Text Solution

    |

  11. The potential energy of a particle of mass 1 kg U = 10 + (x-2)^(2). He...

    Text Solution

    |

  12. A body is moving is down an inclined plane of slope 37^@ the coefficie...

    Text Solution

    |

  13. A force of F=0.5 N is applied on lower block as shown in figure. The w...

    Text Solution

    |

  14. A bead of mass 1/2 kg starts from rest from A to move in a vertical pl...

    Text Solution

    |

  15. A car of mass m is accelerating on a level smooth road under the actio...

    Text Solution

    |

  16. An ideal massless spring S can be compressed 1 m by a force of 100 N i...

    Text Solution

    |

  17. A pendulum of mass 1 kg and length l=1 m is released from rest at angl...

    Text Solution

    |

  18. A small block of mass m is kept on a rough inclined surface of inclina...

    Text Solution

    |

  19. A block A of mass M rests on a wedge B of mass 2M and inclination thet...

    Text Solution

    |

  20. In the figure -3.90 shown, the net work done by the tension when the b...

    Text Solution

    |