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Two bodies of masses 1 kg and 2 kg movin...

Two bodies of masses 1 kg and 2 kg moving with same velocities are stopped by the same force. Then, the ratio of their stopping distances is

A

`1:2`

B

`2:1`

C

`sqrt 2:1`

D

`1:sqrt2`

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The correct Answer is:
To solve the problem of finding the ratio of stopping distances for two bodies of masses 1 kg and 2 kg moving with the same velocity and stopped by the same force, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information**: - Mass of the first body, \( m_1 = 1 \, \text{kg} \) - Mass of the second body, \( m_2 = 2 \, \text{kg} \) - Both bodies are moving with the same velocity, \( v \). 2. **Understand the Concept of Stopping Distance**: - The stopping distance \( s \) can be derived from the work-energy principle, which states that the work done by the force is equal to the change in kinetic energy. - The kinetic energy (KE) of an object is given by the formula: \[ KE = \frac{1}{2} m v^2 \] 3. **Calculate the Kinetic Energies**: - For the first body: \[ KE_1 = \frac{1}{2} m_1 v^2 = \frac{1}{2} (1) v^2 = \frac{1}{2} v^2 \] - For the second body: \[ KE_2 = \frac{1}{2} m_2 v^2 = \frac{1}{2} (2) v^2 = v^2 \] 4. **Relate Kinetic Energy to Stopping Distance**: - According to the work-energy principle, the work done by the force to stop the body is equal to the kinetic energy: \[ F \cdot s = KE \] - For the first body: \[ F \cdot s_1 = KE_1 \Rightarrow s_1 = \frac{KE_1}{F} \] - For the second body: \[ F \cdot s_2 = KE_2 \Rightarrow s_2 = \frac{KE_2}{F} \] 5. **Find the Ratio of Stopping Distances**: - The ratio of stopping distances \( \frac{s_1}{s_2} \) can be expressed as: \[ \frac{s_1}{s_2} = \frac{KE_1 / F}{KE_2 / F} = \frac{KE_1}{KE_2} \] - Substitute the values of kinetic energies: \[ \frac{s_1}{s_2} = \frac{\frac{1}{2} v^2}{v^2} = \frac{1/2}{1} = \frac{1}{2} \] 6. **Conclusion**: - Therefore, the ratio of the stopping distances is: \[ \frac{s_1}{s_2} = \frac{1}{2} \quad \text{or} \quad s_1 : s_2 = 1 : 2 \] ### Final Answer: The ratio of their stopping distances is \( 1 : 2 \).

To solve the problem of finding the ratio of stopping distances for two bodies of masses 1 kg and 2 kg moving with the same velocity and stopped by the same force, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information**: - Mass of the first body, \( m_1 = 1 \, \text{kg} \) - Mass of the second body, \( m_2 = 2 \, \text{kg} \) - Both bodies are moving with the same velocity, \( v \). ...
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