How much work must work be done by a for...

How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms^(-1)` is 10 s?

`10^(3) J`

`10^(4) J`

`2xx10^(3) J`

`4xx10^(4) J`

Text Solution

Verified by Experts

The correct Answer is:

(b) `W=KE=(1)/(2)mv^(2)=10^(4)J`

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