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Under the action of a force F = Cx, the ...

Under the action of a force F = Cx, the position of a body changes from 0 to x. The work done is

A

`(1)/(2)Cx^(2)`

B

`Cx^(2)`

C

Cx

D

`(1)/(2)C x`

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The correct Answer is:
To solve the problem of finding the work done under the action of a force \( F = Cx \) as the position of a body changes from \( 0 \) to \( x \), we can follow these steps: ### Step 1: Understand the Work Done Formula The work done \( W \) by a variable force can be calculated using the integral of the force over the distance moved. The formula is given by: \[ W = \int_{x_1}^{x_2} F \, dx \] where \( F \) is the force and \( x_1 \) and \( x_2 \) are the initial and final positions, respectively. ### Step 2: Substitute the Force In this case, the force is given as \( F = Cx \). We need to substitute this into the work done formula: \[ W = \int_{0}^{x} Cx \, dx \] ### Step 3: Factor Out the Constant Since \( C \) is a constant, we can factor it out of the integral: \[ W = C \int_{0}^{x} x \, dx \] ### Step 4: Perform the Integration Now we need to integrate \( x \): \[ \int x \, dx = \frac{x^2}{2} \] Thus, we can write: \[ W = C \left[ \frac{x^2}{2} \right]_{0}^{x} \] ### Step 5: Evaluate the Integral Now we evaluate the definite integral from \( 0 \) to \( x \): \[ W = C \left( \frac{x^2}{2} - \frac{0^2}{2} \right) = C \left( \frac{x^2}{2} \right) \] ### Step 6: Final Expression for Work Done Therefore, the work done \( W \) is: \[ W = \frac{Cx^2}{2} \] ### Conclusion The work done under the action of the force \( F = Cx \) as the position changes from \( 0 \) to \( x \) is: \[ W = \frac{Cx^2}{2} \] ---

To solve the problem of finding the work done under the action of a force \( F = Cx \) as the position of a body changes from \( 0 \) to \( x \), we can follow these steps: ### Step 1: Understand the Work Done Formula The work done \( W \) by a variable force can be calculated using the integral of the force over the distance moved. The formula is given by: \[ W = \int_{x_1}^{x_2} F \, dx \] where \( F \) is the force and \( x_1 \) and \( x_2 \) are the initial and final positions, respectively. ...
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