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The shortest distance travelled by a par...

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to `(sqrt(3)//2)` times its amplitude. Determine its time period.

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To solve the problem step by step, we will follow the reasoning outlined in the video transcript. ### Step 1: Understand the problem We are given that the shortest distance travelled by a particle executing simple harmonic motion (SHM) from the mean position in 2 seconds is equal to \(\frac{\sqrt{3}}{2}\) times its amplitude \(A\). We need to determine the time period \(T\) of the motion. ### Step 2: Set up the equation for SHM In SHM, the displacement \(x\) from the mean position can be expressed as: \[ ...
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