A particle executes SHM with a time period of 2s and amplitude 10 cm . Find its (i) Displacement (ii) Velocity (iii) Acceleration after 1/6 s, Starting from mean position.

Explanation

To solve the problem step-by-step, we will find the displacement, velocity, and acceleration of a particle executing simple harmonic motion (SHM) after \( \frac{1}{6} \) seconds, given the time period \( T = 2 \) seconds and amplitude \( A = 10 \) cm.

### Step 1: Find the angular frequency \( \omega \)

The angular frequency \( \omega \) is related to the time period \( T \) by the formula:

\[
\omega = \frac{2\pi}{T}
...