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A particle of mass 0.2 kg is excuting SH...

A particle of mass 0.2 kg is excuting SHM of amplitude 0.2 m. When it passes through the mean position its kinetic energy is `64 xx 10^(-3) J` . Obtain the equation of motion of this particle if the initial phase of oscillation is `pi//4`.

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To solve the problem step by step, we will follow the outlined process to obtain the equation of motion for the particle executing simple harmonic motion (SHM). ### Step 1: Identify Given Values - Mass of the particle, \( m = 0.2 \, \text{kg} \) - Amplitude of SHM, \( A = 0.2 \, \text{m} \) - Kinetic energy at mean position, \( KE = 64 \times 10^{-3} \, \text{J} \) - Initial phase, \( \phi = \frac{\pi}{4} \) ...
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