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A block whose mass is 2 kg is fastened o...

A block whose mass is 2 kg is fastened on a spring whose spring constant is 100 `Nm^(-1)` . It is pulled to a distance of 0.1 m from over a frictionless surface and is released at t=0. Calculate the kinetic eneryg of the block when it is 0.05 m away from its mean position.

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To solve the problem, we need to calculate the kinetic energy of a block attached to a spring when it is 0.05 m away from its mean position. Let's break it down step by step. ### Step 1: Identify the given values - Mass of the block, \( m = 2 \, \text{kg} \) - Spring constant, \( k = 100 \, \text{N/m} \) - Amplitude (maximum displacement), \( A = 0.1 \, \text{m} \) - Displacement from the mean position, \( x = 0.05 \, \text{m} \) ...
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