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The bob of simple pendulum executes SHM ...

The bob of simple pendulum executes SHM in water with a period T, while the period of oscillation of the bob is `T_(0)` in air. Neglecting frictional force of water and given that the density of the bob is `(4000)/(3)kgm^(-3)` , find the ration between T and `T_(0)`.

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To find the ratio between the period of oscillation of the bob in water (T) and in air (T₀), we can follow these steps: ### Step 1: Understand the period of a simple pendulum The period of a simple pendulum in air is given by the formula: \[ T_0 = 2\pi \sqrt{\frac{L}{g}} \] where: - \( T_0 \) is the period in air, - \( L \) is the length of the pendulum, ...
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