Home
Class 11
PHYSICS
The length of a simple pendulum is 16 c...

The length of a simple pendulum is 16 cm . It is suspended by the roof of a lift which is moving upwards with an accleration of `6.2 ms^(-2)` . Find the time period of pendulum.

Text Solution

AI Generated Solution

To solve the problem, we need to find the time period of a simple pendulum suspended in a lift that is accelerating upwards. Here’s the step-by-step solution: ### Step 1: Identify the given values - Length of the pendulum (L) = 16 cm = 0.16 m - Acceleration of the lift (a) = 6.2 m/s² - Acceleration due to gravity (g) = 9.8 m/s² ### Step 2: Determine the effective gravitational acceleration (g_eff) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A simple pendulum with a bob of mass m is suspended from the roof of a car moving with horizontal acceleration a

The length of the simple pendulum is 40 cm. Calculate its time period.

The length of a simple pendulum is made one-fourth. Its time period becomes :

The time period of a simple pendulum is 2 s. Find its frequency .

If the length of a simple pendulum is increased by 2%, then the time period

The time period of a simple pendulum is 2 s. What is its frequency?

The time period of a simple pendulum of length 9.8 m is

The time period of simple pendulum inside a stationary lift is T. If lift starts accelerating upwards with the acceleration of g/2, then the new time period of the simple pendulum will be

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/6, then the period of the pendulum will be

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be