If the earth were a homegeneous sphere and a straight hole was bored in it through its centre, so when a body is dropped in the hole, it will excutes SHM. Determine the time period of its oscillation . Radius of the earth is `6.4 xx 10^(6)` m and `g=9.8 ms^(-2)`

Explanation

To determine the time period of oscillation of a body dropped into a straight hole bored through the center of a homogeneous Earth, we can use the formula for the time period of simple harmonic motion (SHM) in this context.

### Step-by-Step Solution:

1. **Identify the Formula**:
The time period \( T \) of a body executing SHM in a gravitational field can be expressed as:
\[
T = 2\pi \sqrt{\frac{R_e}{g}}
...