A liquid of mss m is set into oscillations in a U-tube of cross section A. Its time period recorded is T, where `T=2pisqrt(l//2g)` , here l is the length of liquid column. If the liquid of same mass is set into oscillations in U-tube of cross-section A/16 then determine time period of oscillation.

Explanation

To solve the problem, we need to determine the new time period of oscillation when the cross-section area of the U-tube is changed from A to A/16. We will start with the formula for the time period of oscillation given in the question and analyze how the change in cross-section affects it.

### Step-by-Step Solution:

1. **Understand the Original Time Period**:
The original time period \( T \) is given by the formula:
\[
T = 2\pi \sqrt{\frac{l}{2g}}
...