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The amplitude and the time period in a S...

The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is `pi//2` radian, then the equation of S.H.M. will be

A

y=0.5 sin 5`pit`

B

y=0.5 sin 4`pit`

C

y=0.5 sin 2.5`pit`

D

y=0.5 cos `5pit`

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The correct Answer is:
To find the equation of Simple Harmonic Motion (S.H.M.) given the amplitude, time period, and initial phase, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values:** - Amplitude (A) = 0.5 cm - Time Period (T) = 0.4 seconds - Initial Phase (φ) = π/2 radians 2. **Convert Amplitude to Meters (if necessary):** - Since the amplitude is given in centimeters, we can convert it to meters: \[ A = 0.5 \text{ cm} = 0.005 \text{ m} \] 3. **Calculate Angular Frequency (ω):** - The angular frequency (ω) is related to the time period (T) by the formula: \[ \omega = \frac{2\pi}{T} \] - Substituting the given time period: \[ \omega = \frac{2\pi}{0.4} = 5\pi \text{ rad/s} \] 4. **Write the Standard Equation of S.H.M.:** - The standard equation for S.H.M. can be written as: \[ x(t) = A \sin(\omega t + \phi) \] - Substituting the values of A, ω, and φ: \[ x(t) = 0.005 \sin(5\pi t + \frac{\pi}{2}) \] 5. **Simplify Using Trigonometric Identity:** - We know that: \[ \sin\left(\frac{\pi}{2} + \theta\right) = \cos(\theta) \] - Therefore, we can rewrite the equation as: \[ x(t) = 0.005 \cos(5\pi t) \] 6. **Final Equation:** - The final equation of S.H.M. is: \[ x(t) = 0.005 \cos(5\pi t) \] - If we convert back to centimeters: \[ x(t) = 0.5 \cos(5\pi t) \text{ cm} \] ### Conclusion: The equation of S.H.M. is: \[ x(t) = 0.5 \cos(5\pi t) \text{ cm} \] Thus, the correct option is \( y = 0.5 \cos(5\pi t) \). ---

To find the equation of Simple Harmonic Motion (S.H.M.) given the amplitude, time period, and initial phase, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values:** - Amplitude (A) = 0.5 cm - Time Period (T) = 0.4 seconds - Initial Phase (φ) = π/2 radians ...
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