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The total energy of a particle having a ...

The total energy of a particle having a displacement x, executing simple harmonic motion is

A

`prop x`

B

`prop x^(2)`

C

independent of x

D

`prop x^(1//2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the total energy of a particle executing simple harmonic motion (SHM) with displacement \( x \), we can follow these steps: ### Step 1: Understand the Components of Total Energy The total energy \( E \) of a particle in simple harmonic motion is the sum of its kinetic energy (KE) and potential energy (PE). ### Step 2: Write the Expressions for Kinetic and Potential Energy The kinetic energy \( KE \) of a particle in SHM is given by: \[ KE = \frac{1}{2} m \omega^2 (A^2 - x^2) \] where: - \( m \) is the mass of the particle, - \( \omega \) is the angular frequency, - \( A \) is the amplitude of the motion, - \( x \) is the displacement from the mean position. The potential energy \( PE \) is given by: \[ PE = \frac{1}{2} m \omega^2 x^2 \] ### Step 3: Calculate the Total Energy Now, we can find the total energy \( E \) by adding the kinetic and potential energy: \[ E = KE + PE \] Substituting the expressions we have: \[ E = \left(\frac{1}{2} m \omega^2 (A^2 - x^2)\right) + \left(\frac{1}{2} m \omega^2 x^2\right) \] ### Step 4: Simplify the Expression Now, simplifying the total energy expression: \[ E = \frac{1}{2} m \omega^2 (A^2 - x^2) + \frac{1}{2} m \omega^2 x^2 \] \[ E = \frac{1}{2} m \omega^2 A^2 - \frac{1}{2} m \omega^2 x^2 + \frac{1}{2} m \omega^2 x^2 \] The \( -\frac{1}{2} m \omega^2 x^2 \) and \( +\frac{1}{2} m \omega^2 x^2 \) cancel each other out: \[ E = \frac{1}{2} m \omega^2 A^2 \] ### Step 5: Conclusion From the final expression for total energy \( E = \frac{1}{2} m \omega^2 A^2 \), we can see that the total energy is dependent only on the mass \( m \), angular frequency \( \omega \), and amplitude \( A \). It does not depend on the displacement \( x \). Thus, the total energy of a particle executing simple harmonic motion is **independent of \( x \)**. ### Final Answer The correct option is **3) independent of x**. ---

To solve the question regarding the total energy of a particle executing simple harmonic motion (SHM) with displacement \( x \), we can follow these steps: ### Step 1: Understand the Components of Total Energy The total energy \( E \) of a particle in simple harmonic motion is the sum of its kinetic energy (KE) and potential energy (PE). ### Step 2: Write the Expressions for Kinetic and Potential Energy The kinetic energy \( KE \) of a particle in SHM is given by: \[ ...
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