If length of a simple pendulum is increa...

If length of a simple pendulum is increased by 69%, then the percentage increase in its time period is

A

0.11

B

0.21

C

0.42

D

`10.5%`

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The correct Answer is:

D

(d) As, `T=2pisqrt((l)/(g))implies (DeltaT)/(T)=(1)/(2)(Deltal)/(l)`
Given , `(Deltal)/(l)=21%`
`implies (DeltaT)/(T)=(1)/(2)xx 21%=10.5 %`

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