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Three mass 0.1 kg ,0.3 kg and 0.4 kg are...

Three mass 0.1 kg ,0.3 kg and 0.4 kg are suspended at end of a spring. When is 0.4 kg mass is removed , the system oscillates with a period 2 s . When the 0.3 kg mass is also removed , the system will oscillates with a period

A

1 s

B

2 s

C

3 s

D

4 s

Text Solution

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The correct Answer is:
To solve the problem step by step, we will determine the period of oscillation when the 0.3 kg mass is also removed from the spring-mass system. ### Step-by-Step Solution: 1. **Identify the initial conditions**: - We have three masses: \( m_1 = 0.1 \, \text{kg} \), \( m_2 = 0.3 \, \text{kg} \), and \( m_3 = 0.4 \, \text{kg} \). - When the 0.4 kg mass is removed, the remaining mass is \( m_1 + m_2 = 0.1 \, \text{kg} + 0.3 \, \text{kg} = 0.4 \, \text{kg} \). 2. **Use the formula for the period of a spring-mass system**: The period \( T \) of a mass-spring system is given by: \[ T = 2\pi \sqrt{\frac{m}{k}} \] where \( m \) is the mass and \( k \) is the spring constant. 3. **Set up the equation for the first scenario**: - When the 0.4 kg mass is removed, the period is given as \( T = 2 \, \text{s} \). - Thus, we have: \[ 2 = 2\pi \sqrt{\frac{0.4}{k}} \] - Dividing both sides by \( 2\pi \): \[ \frac{1}{\pi} = \sqrt{\frac{0.4}{k}} \] - Squaring both sides: \[ \frac{1}{\pi^2} = \frac{0.4}{k} \] - Rearranging gives: \[ k = 0.4\pi^2 \] 4. **Set up the equation for the second scenario**: - Now, we need to find the period when the 0.3 kg mass is also removed, leaving only the 0.1 kg mass. - The new mass \( m = 0.1 \, \text{kg} \). 5. **Calculate the new period**: - Using the same formula for the period: \[ T = 2\pi \sqrt{\frac{0.1}{k}} \] - Substituting \( k = 0.4\pi^2 \): \[ T = 2\pi \sqrt{\frac{0.1}{0.4\pi^2}} \] - Simplifying: \[ T = 2\pi \sqrt{\frac{0.1}{0.4}} \cdot \frac{1}{\pi} = 2\sqrt{\frac{0.1}{0.4}} = 2\sqrt{\frac{1}{4}} = 2 \cdot \frac{1}{2} = 1 \, \text{s} \] 6. **Conclusion**: - The period of oscillation when the 0.3 kg mass is also removed is \( T = 1 \, \text{s} \). ### Final Answer: The period of oscillation when the 0.3 kg mass is also removed is **1 second**.

To solve the problem step by step, we will determine the period of oscillation when the 0.3 kg mass is also removed from the spring-mass system. ### Step-by-Step Solution: 1. **Identify the initial conditions**: - We have three masses: \( m_1 = 0.1 \, \text{kg} \), \( m_2 = 0.3 \, \text{kg} \), and \( m_3 = 0.4 \, \text{kg} \). - When the 0.4 kg mass is removed, the remaining mass is \( m_1 + m_2 = 0.1 \, \text{kg} + 0.3 \, \text{kg} = 0.4 \, \text{kg} \). ...
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