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Two bodies (M) and (N) of equal masses a...

Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.

A

`(k_(1))/(k_(2))`

B

`sqrt((k_(1))/(k_(2)))`

C

`(k_(2))/(k_(1))`

D

`sqrt((k_(2))/(k_(1)))`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the given information and apply the relevant formulas for simple harmonic motion (SHM). ### Step 1: Understand the System We have two bodies, M and N, each suspended from separate massless springs with spring constants \( k_1 \) and \( k_2 \) respectively. Both bodies have equal mass \( m \). ### Step 2: Identify the Maximum Velocity in SHM The maximum velocity \( v_{max} \) of a body in simple harmonic motion is given by the formula: \[ v_{max} = A \omega \] where \( A \) is the amplitude of the oscillation and \( \omega \) is the angular frequency. ### Step 3: Express Angular Frequency The angular frequency \( \omega \) for a mass-spring system is given by: \[ \omega = \sqrt{\frac{k}{m}} \] Thus, for body M: \[ \omega_1 = \sqrt{\frac{k_1}{m}} \] And for body N: \[ \omega_2 = \sqrt{\frac{k_2}{m}} \] ### Step 4: Set Up the Equation for Maximum Velocities Since it is given that the maximum velocities of both bodies are equal, we can write: \[ A_1 \omega_1 = A_2 \omega_2 \] Substituting the expressions for \( \omega_1 \) and \( \omega_2 \): \[ A_1 \sqrt{\frac{k_1}{m}} = A_2 \sqrt{\frac{k_2}{m}} \] ### Step 5: Simplify the Equation We can cancel \( m \) from both sides: \[ A_1 \sqrt{k_1} = A_2 \sqrt{k_2} \] ### Step 6: Solve for the Ratio of Amplitudes Rearranging the equation gives: \[ \frac{A_1}{A_2} = \frac{\sqrt{k_2}}{\sqrt{k_1}} \] Thus, the ratio of the amplitudes of vibration of M to that of N is: \[ \frac{A_1}{A_2} = \sqrt{\frac{k_2}{k_1}} \] ### Final Answer The ratio of the amplitude of vibration of M to that of N is: \[ \frac{A_1}{A_2} = \sqrt{\frac{k_2}{k_1}} \]

To solve the problem step by step, we will analyze the given information and apply the relevant formulas for simple harmonic motion (SHM). ### Step 1: Understand the System We have two bodies, M and N, each suspended from separate massless springs with spring constants \( k_1 \) and \( k_2 \) respectively. Both bodies have equal mass \( m \). ### Step 2: Identify the Maximum Velocity in SHM The maximum velocity \( v_{max} \) of a body in simple harmonic motion is given by the formula: \[ ...
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