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A mass M is attached to a horizontal spr...

A mass M is attached to a horizontal spring of force constant k fixed one side to a rigid support as shown in figure. The mass oscillates on a frictionless surface with time period T and amplitude A. When the mass M is in equilibrium position, another mass m is gently placed on it. When will be the new amplitude of ocillation?

A

`sqrt(((M+m))/(M))A`

B

`sqrt(((M-m))/(M))A`

C

`sqrt((M)/((M+m)))A`

D

`sqrt((M)/((M-m)))A`

Text Solution

Verified by Experts

The correct Answer is:
C

(c) `(P_(i)=P_(f))`
Law of conservation of momentum
`Mv_("max")=(m+M)v`
`impliesv_("max")=(Mv_("max"))/((m+M))`
`because v_("max")=A'omega'`
`implies (M.A)/((m+M))sqrt((k)/(M))=A'sqrt((k)/((m+M)))`
`implies A'=Asqrt((M)/((m+M)))`
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