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In the equation y=Asin(omegat+pi/4) matc...

In the equation `y=Asin(omegat+pi/4)` match the following for x=`A/2`.

Text Solution

Verified by Experts

The correct Answer is:
`(A rarr q, B rarr s,C rarr p)`
`v=omegasqrt(A^(2)-(A^(2))/(4))=(sqrt(3))/(2)omegaA=(sqrt(3))/(2)v_("max")`
`therefore K=((sqrt(3))/(2))^(2)` times
`K_("max")=(3)/(4)K_("max")`
About PE, it will be `(1)/(4)` times its maximum value only when potential energy at mean position is zero.
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