A 2 kg mass is suspended by a rubber cord 2 m long and of cross-section 0.5 cm. It is made to describe a horizontal circle of radius 50cm in 4 times a second. Find the extension of the cord.(Young's modulus `Y=7xx10^(8) Nm^(-2)`)

Explanation

To solve the problem step by step, we will follow the physics principles involved in circular motion and elasticity.

### Step 1: Identify the given values
- Mass (m) = 2 kg
- Length of the rubber cord (L) = 2 m
- Cross-sectional area (A) = 0.5 cm² = 0.5 × 10^(-4) m² (convert to m²)
- Radius of the horizontal circle (r) = 50 cm = 0.5 m (convert to meters)
- Frequency (f) = 4 Hz
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