What is the density of lead under a pressure of `2xx10^(8)Nm^(-2)` , if the bulk modulus of lead is `8xx10^(9)Nm^(-2)` and initially the density of lead is `11.4 g cm^(-3)` ?

Explanation

To find the density of lead under a pressure of \(2 \times 10^{8} \, \text{N/m}^2\), given that the bulk modulus of lead is \(8 \times 10^{9} \, \text{N/m}^2\) and the initial density is \(11.4 \, \text{g/cm}^3\), we can use the formula for the change in density due to pressure:

\[ \rho' = \frac{\rho}{1 - \frac{\Delta P}{B}} \]

where:
- \(\rho'\) is the new density,
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