A square lead slab of side 50cm and thickness 5.0cm is subjected to a shearing force (on its narrow face) of magnitude `9.0xx10^(4)` N. The lower edge is riveted to the floor. How much is the upper edge displaced, if the shear modulus of lead is `5.6xx10^(90)` Pa?

Explanation

To solve the problem, we need to calculate the displacement (ΔL) of the upper edge of the lead slab when a shearing force is applied. We will use the formula for shear strain and shear modulus.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Side of the square slab (L) = 50 cm = 0.50 m
- Thickness of the slab (x) = 5 cm = 0.05 m
- Shearing force (F) = 9.0 × 10^4 N
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