Calculate the work done in streching a steel wire of Young's modulus of `2xx10^(11) Nm^(-2)` mass of 40kg,length of 200 cm and area of cross-section is 0.06 `cm^(2)` slowly applied without the elastic limit being reached.

Explanation

To calculate the work done in stretching a steel wire, we will follow these steps:

### Step 1: Convert all measurements to SI units
- Length of the wire: \( L = 200 \, \text{cm} = 200 \times 10^{-2} \, \text{m} = 2 \, \text{m} \)
- Area of cross-section: \( A = 0.06 \, \text{cm}^2 = 0.06 \times 10^{-4} \, \text{m}^2 = 6 \times 10^{-6} \, \text{m}^2 \)
- Mass of the wire: \( m = 40 \, \text{kg} \)

### Step 2: Calculate the force applied on the wire
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