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A wire of length 2.5 m has a percentage ...

A wire of length 2.5 m has a percentage strain of 0.012% under a tensile force. The extension produce in the wire will be

A

0.03 mm

B

0.3 mm

C

0.3 mm

D

0.03 m

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The correct Answer is:
To find the extension produced in the wire, we can follow these steps: ### Step 1: Understand the given data - Length of the wire (L) = 2.5 m - Percentage strain = 0.012% ### Step 2: Convert percentage strain to a decimal Percentage strain is given as 0.012%. To convert this to a decimal, we divide by 100: \[ \text{Strain} = \frac{0.012}{100} = 0.00012 \] ### Step 3: Use the formula for extension The formula relating extension (ΔL) to strain is given by: \[ \text{Strain} = \frac{\Delta L}{L} \] Rearranging this formula to find the extension (ΔL): \[ \Delta L = \text{Strain} \times L \] ### Step 4: Substitute the values into the formula Now, we substitute the values we have: \[ \Delta L = 0.00012 \times 2.5 \] ### Step 5: Calculate the extension Calculating the above expression: \[ \Delta L = 0.00012 \times 2.5 = 0.0003 \text{ m} \] ### Step 6: Convert the extension to millimeters To convert meters to millimeters, we multiply by 1000: \[ \Delta L = 0.0003 \text{ m} \times 1000 = 0.3 \text{ mm} \] ### Final Answer The extension produced in the wire will be **0.3 mm**. ---

To find the extension produced in the wire, we can follow these steps: ### Step 1: Understand the given data - Length of the wire (L) = 2.5 m - Percentage strain = 0.012% ### Step 2: Convert percentage strain to a decimal Percentage strain is given as 0.012%. To convert this to a decimal, we divide by 100: ...
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