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The work per unit volume to stretch the ...

The work per unit volume to stretch the length by `1%` of a wire with cross sectional area of `1mm^2` will be. `[Y=9xx10^(11)(N)/(m^2)`]

A

`9xx10^(11) J`

B

`4.5 xx 10^(7) J`

C

`9xx10^(7) J`

D

`4.5 xx 10^(11) J`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) The work per unit volume
`U=(1)/(2)xxYxx("Strain")^(2)=(1)/(2)xx9xx10^(11)xx((1)/(100))^(2)`
`=4.5xx10^(7) J`
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