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When a load of 10 kg is hung from the wi...

When a load of 10 kg is hung from the wire, then extension of 2m is produced. Then work done by restoring force is

A

200 J

B

100 J

C

50 J

D

25 J

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `W=(1)/(2)` (Maximum stretching force)`xx`(Elongation produced)
`=(1)/(2)F Delta l`
Here, `F=mg=10xx10`
`Deltal=2m`
`therefore W=(1)/(2)(10xx10)xx2=100J`
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