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Determine the force required to double t...

Determine the force required to double the length of the steel wire of area of cross-section `5 xx 10^(-5) m^(2)`. Give Y for steel `= 2 xx 10^(11) Nm^(-2)`.

A

`2 xx10^(7) N`

B

`2xx10^(6) N`

C

`2xx10^(8) N`

D

`2xx10^(5) N`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Stress required to double the length is called Young's modulus.
`therefore Y=(F)/(A)` or `F=Y.A=2xx10^(11)=2xx10^(7) N`
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