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A metal block is experiencing an atmosph...

A metal block is experiencing an atmospheric pressure of `1 xx 10^(5)N//m^(2)`, when the same block is placed vacuum chamber, the freactional change in its volume is (the bulk modulus of metal is `1.25 xx 10^(11) N//m^(2)`)

A

`4xx10^(-7)`

B

`2xx10^(-7)`

C

`8xx10^(-7)`

D

`1xx10^(-7)`

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The correct Answer is:
To solve the problem, we need to find the fractional change in volume of a metal block when it is subjected to a change in pressure. The relevant formula involves the bulk modulus of the material. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Atmospheric pressure, \( P_1 = 1 \times 10^5 \, \text{N/m}^2 \) - Bulk modulus of the metal, \( B = 1.25 \times 10^{11} \, \text{N/m}^2 \) - Pressure in a vacuum chamber, \( P_2 = 0 \, \text{N/m}^2 \) (since it is a vacuum) 2. **Calculate the Change in Pressure (\( \Delta P \)):** \[ \Delta P = P_2 - P_1 = 0 - (1 \times 10^5) = -1 \times 10^5 \, \text{N/m}^2 \] 3. **Use the Formula for Bulk Modulus:** The bulk modulus \( B \) is defined as: \[ B = -\frac{\Delta P}{\frac{\Delta V}{V}} \] Rearranging this gives: \[ \frac{\Delta V}{V} = -\frac{\Delta P}{B} \] 4. **Substitute the Values into the Formula:** \[ \frac{\Delta V}{V} = -\frac{-1 \times 10^5}{1.25 \times 10^{11}} \] \[ \frac{\Delta V}{V} = \frac{1 \times 10^5}{1.25 \times 10^{11}} \] 5. **Calculate the Fractional Change in Volume:** \[ \frac{\Delta V}{V} = \frac{1}{1.25} \times 10^{-6} = 0.8 \times 10^{-6} = 8 \times 10^{-7} \] ### Final Result: The fractional change in volume of the metal block when placed in a vacuum chamber is: \[ \frac{\Delta V}{V} = 8 \times 10^{-7} \]

To solve the problem, we need to find the fractional change in volume of a metal block when it is subjected to a change in pressure. The relevant formula involves the bulk modulus of the material. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Atmospheric pressure, \( P_1 = 1 \times 10^5 \, \text{N/m}^2 \) - Bulk modulus of the metal, \( B = 1.25 \times 10^{11} \, \text{N/m}^2 \) - Pressure in a vacuum chamber, \( P_2 = 0 \, \text{N/m}^2 \) (since it is a vacuum) ...
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