Calculate the apprroximate change in density of water in a lake at a depth of `400 m ` below the surface. The density of water at the surface id `1030 kg//m^(3)` and bulk modulus of water is `2xx10^(9) N//m^(2)`.

Options

A. `4 kgm^(-3)`
B. `2 kgm^(-3)`
C. `6 kgm^(-3)`
D. `8 kgm^(-3)`

Answer

B

Explanation

(b) The density of water `drho=(rho)/(B)*dp`
`dp=rhogh=(1030)(10)(400)=4.12xx10^(6) Nm^(-2)`
`therefore dp=(1030)/(2xx10^(9)xx4.12xx10^(6)=2.12 Kgm^(-3)`