A string 1m long is drawn by a 300 Hz vibrator attached to its end. The string vibrates in three segments. The speed of transverse waves in the string is equal to

Options

A. 1.22v
B. 0.61v
C. 1.50v
D. 0.75v

Answer

A

Explanation

(a) According to the question , `T prop x, T' prop (1.5 x)`
We have, `v_(s) prop sqrt(T)" "(therefore v_(s)=sqrt((T)/(mu)))`
`therefore (v'_(s))/(v_(s))=sqrt((T')/(T))=sqrt((1.5x)/(x))=sqrt(1.5)`
The speed of sound `v'_(s)=sqrt(1.5)v_(s)=sqrt(1.5)v=1.22v`