The volume of mercury in the bulb of thermometer is `10^(-6) m^(3)`. The area of cross-section of the capillary tube is `2 xx 10^(-7) m^(2)`. If the temperature is raised by `100^(0)C`, the increase in the length of the mercury column is `(gamma_(Hg) = 18 xx 10^(-5//@)C)`

Explanation

To solve the problem step by step, we will follow the principles of thermal expansion and the relationship between volume, area, and length in a capillary tube.

### Step 1: Understand the Given Data
- Volume of mercury in the bulb, \( V = 10^{-6} \, m^3 \)
- Area of cross-section of the capillary tube, \( A = 2 \times 10^{-7} \, m^2 \)
- Temperature change, \( \Delta T = 100 \, ^\circ C \)
- Coefficient of cubical thermal expansion for mercury, \( \gamma_{Hg} = 18 \times 10^{-5} \, \text{per } ^\circ C \)

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