At what temperarture, the kinetic energy of a gas molecule is half of the value at `27^(@)C.` ?

Explanation

To solve the problem, we need to determine the temperature at which the kinetic energy of a gas molecule is half of the value at \(27^\circ C\). Here are the steps to arrive at the solution:

### Step 1: Understand the relationship between kinetic energy and temperature
The kinetic energy (KE) of a gas molecule is given by the formula:
\[ KE = \frac{3}{2} k T \]
where \(k\) is the Boltzmann constant and \(T\) is the absolute temperature in Kelvin. This indicates that kinetic energy is directly proportional to the temperature.
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