Prove that the pressure of an ideal gas is numerically equal to two third of the mean translational kinetic energy per unit volume of the gas.

Explanation

Translational `kE` per unit volume
`E=(1)/(2)` ( mass perunit volume) `(v^(2))=(1)/(2)(p)((3p)/(p)=(3)/(2)p)`
`or" " p=(2)/(3)E`