For a molecule of an ideal gas `n=3xx10^(8)cm^(-3)` and mean free path is `10^(-2)` cm. Calculate the diameter of the molecule.

Explanation

To calculate the diameter of a molecule of an ideal gas given the number density \( n \) and the mean free path \( L \), we can use the formula for mean free path:

\[ L = \frac{1}{\sqrt{2} \pi n d^2} \]

Where:
- \( L \) is the mean free path,
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