If pressure of `CO_(2)` (real gas ) in a container is given by `P = (RT)/(2V - b) - (a)/(4b^(2))`, then mass of the gas in container is a) 11g b) 22g c) 33g d) 44g

Explanation

van der Waals' gas equation for n mole of real gas
`(p+(n^(2)a)/(V_(2)))(V-nb)=nRT`
`P+(N^(2)a)/(V_(2))=(nRT)/(V-nb)`
`therefore" " p=((nRT)/(V-nb))-(n_(2)a)/(V_(2))`
Given equation, `" " p=((RT)/(2V-b)-a/(4b^(2)))` On comparing the given equation with this standard equation, we get,`" " n=1//2`
Hence `" " n=m/M`
`rArr` mass of gas,m `=nM1/2xx44=22g`