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A clock with a metal pendulum beating se...

A clock with a metal pendulum beating seconds keeps correct time at `0^(@)C.` If it loses 12.5s a day at `25^(@)C` the coefficient of linear expansion of metal pendulum is

A

`(1)/(86400)//^(@)C`

B

`(1)/(43200)//^(@)C`

C

`(1)/(14400)//^(@)C`

D

`(1)/(28800)//^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A

Number of seconds lost in day
`" "Deltat=1/2 alpha Delta theta xx 86400`
The coefficient of linear expansion of metal pendulum
`alpha=(2Deltat)/(Delta thetaxx86400)=(2xx12.5)/(25xx86400)rArralpha=1/(86400)//^(@)C`
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