A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.
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Let a wire of length L is bent in a circular form of raidus r. Then `2pir=L=Rightarrow=(L)/(2pi) ……………..(i)` The magnetic dipole moment of a circular ring, `" " M=IA " " ("where, A is area of the ring")` `or" " M=Ipir^(2) ` `" " M=Ipi((I)/(2pi))^(2)` `" " M=Ipixx(L^(2))/(4pi^(2)` `" " M=(IL^(2))/(4pi)A-m^(2)`
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