A closely wound solenoid of 800 turns and area of cross section `2*5xx10^-4m^2` carries a current of `3*0A`. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?
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It is given that number of turns, N=800N Area of cross-section, A=`2.5xx10^(4)m^(2)` Now, magnetic moment of the solenoid is `" " M=NIA=800xx3.0xx2.5xx10^(-4)` `" " =0.60JT^(-1)` Which acts along the axis of the solenoid in the direction releated to the sence of flow of current according to right handed screw rule.
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