A bar magnet when placed at an angle of `30^(@)` to the direction of magnetic field of `5xx10^(-2)`T, experiences a moment of couple `2.5xx10^(-6)`. If the length of the magnet is 5cm, then what will be its pole strength?
Text Solution
AI Generated Solution
To solve the problem, we will use the formula for the torque (moment of couple) experienced by a bar magnet in a magnetic field. The torque (τ) can be expressed as:
\[
\tau = m \cdot B \cdot \sin(\theta)
\]
Where:
- \( \tau \) is the torque (moment of couple)
...
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