A short bar magnet of moment `0*32JT^-1` is placed in a uniform external magnetic field of `0*15T`, if the bar is free to rotate in the plane of the field, which orientations would correspond to its, (i) stable and (ii) unstable equilibrium? What is the potential energy of the magnet in each case?
Text Solution
AI Generated Solution
To solve the problem, we need to determine the orientations of the bar magnet that correspond to stable and unstable equilibrium in a uniform magnetic field, as well as calculate the potential energy in each case.
### Step-by-Step Solution:
1. **Understanding the Magnetic Moment and Magnetic Field**:
- The magnetic moment (M) of the bar magnet is given as \(0.32 \, \text{JT}^{-1}\).
- The external magnetic field (B) is given as \(0.15 \, \text{T}\).
...
Topper's Solved these Questions
MAGNETISM AND MATTER
DC PANDEY ENGLISH|Exercise 5.1|15 Videos
MAGNETISM AND MATTER
DC PANDEY ENGLISH|Exercise 5.2|15 Videos
MAGNETICS
DC PANDEY ENGLISH|Exercise MCQ_TYPE|1 Videos
MODERN PHYSICS
DC PANDEY ENGLISH|Exercise Integer Type Questions|17 Videos
Similar Questions
Explore conceptually related problems
A short bar magnet of magnetic moment 0*4JT^-1 is placed in a uniform magnetic field of 0*16T . The magnet is in stable equilibrium when the potencial energy is
A short bar magnet having magnetic moment M=0.80 JT^1 is placed in uniform magnetic field of 0.30 T. If bar magnet is free to rotate in plane of field, then (where U is potential energy and tau is torque)
If there is uniform magnetic field of in the positive z direction , in which orientations the loop would be in (i) stable equilibrium and (ii) unstable equilibrium ?
A magnet of magnetic moment 2JT^(-1) is aligned in the direction of magnetic field of 0.1T . What is the net work done to bring the magnet normal to the magnrtic field?
The potential enargy of bar magnet of magnetic moment 8 Am ^(2) placed in a uniform magnetic field of 2 T at an angle of 120^(@) is equal to
A short bar magnetic is placed in a uniform magnetic field of 0.25 T, with its axis at an angle of 30^(@) with the field. If it experiences a torque of magnitude 4.5xx10^(-2) N m, then its magnetic momentum is
A bar magnet of magnetic moment 6 J//T is aligned at 60^(@) with a uniform external magnetic field of 0.44 T. Calculate (a) the work done in turning the magnet to align its magnetic moment (i) normal to the magnetic field, (ii) opposite to the magnetic field, and (b) the torque on the magnet in the final orientation in case (ii).
A bar magnet of magnetic moment 3.0 A-m^(2) is placed in a uniform magnetic induction field of 2xx10^(-5)T . If each pole of the magnet experiences a force of 6xx10^(-4)N , the length of the magnet is
A short bar magnet pleaced with its axis at 30^(@) with a uniform external magnetic field of 0.16 Tesla expriences a torque of magnitude 0.032 Joule. The magnetic moment of the bar magnet will be
Short bar magnet is place 30degrees with the external magnetic field 0.06T which experiences a torque of 0.018Nm then the minimum work done required to move from its stable equilibrium to unstable equilibrium is
DC PANDEY ENGLISH-MAGNETISM AND MATTER-Medical gallery