A magnetic needle is free to oscillate in a uniform magnetic field as shown in the figure. The magnetic moment of magnetic needle `7.2Am^(2)` and moment of inertia `I=6.5xx10^(-6)kgm^(2)`. The number of oscillation performed in 5s are 10. Calculate the magnitude of magnetic field?
Text Solution
AI Generated Solution
To solve the problem, we need to calculate the magnitude of the magnetic field \( B \) using the given parameters of the magnetic needle. Here are the steps to solve the problem:
### Step 1: Determine the Time Period of Oscillation
The number of oscillations performed in 5 seconds is given as 10. Therefore, the time period \( T \) can be calculated as:
\[
T = \frac{\text{Total time}}{\text{Number of oscillations}} = \frac{5 \text{ s}}{10} = 0.5 \text{ s}
\]
...
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