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A compass needle whose magnetic moment i...

A compass needle whose magnetic moment is `60Am^(2)` pointing geographical north at a certain place where the horizontal component of earth's magnetic field is `40 xx 10^(-6) Wbm^(-2)` experiences a torque of `1.2 xx 10^(-3)Nm`. The declination of the place is

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A compass needle in stable equilibrium position points towards nroth i.e. alon the horizontal components H of earth's magnetic field. When it is turned through the angle of declination `alpha`, so as as to point geographical north, then it experience a torque of magnitude MH sin `alpha`.
`Here, M=60A-m^(2)`
`" " H=40xx10^(-6)Wb//m^(2)`
`therefore " " sin alpha=(1.2xx10^(-3))/(60xx40xx10)=0.5 therefore alpha=30^(@)`
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