Home
Class 12
PHYSICS
In the magnetic meridian of a certain pl...

In the magnetic meridian of a certain place, the horizontal component of earth's magnetic fied is `0.26 G` and the dip angle is `60^@`. Find
a. Vertical component of earth's magnetic field
b. the net magnetic field at this place

Text Solution

AI Generated Solution

To solve the problem, we need to find the vertical component of the Earth's magnetic field and the net magnetic field at a certain place given the horizontal component and the dip angle. ### Given: - Horizontal component of Earth's magnetic field, \( B_H = 0.26 \, \text{G} \) - Dip angle, \( \theta = 60^\circ \) ### Step 1: Find the Vertical Component of Earth's Magnetic Field The relationship between the vertical component \( B_V \) and the horizontal component \( B_H \) in terms of the dip angle \( \theta \) is given by: ...
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    DC PANDEY ENGLISH|Exercise 5.1|15 Videos
  • MAGNETISM AND MATTER

    DC PANDEY ENGLISH|Exercise 5.2|15 Videos
  • MAGNETICS

    DC PANDEY ENGLISH|Exercise MCQ_TYPE|1 Videos
  • MODERN PHYSICS

    DC PANDEY ENGLISH|Exercise Integer Type Questions|17 Videos

Similar Questions

Explore conceptually related problems

The earth's magnetic field is

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0*26G and dip angle is 60^@ . What is the magnetic field of earth at this location?

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0*26G and dip angle is 60^@ . What is the magnetic field of earth at this location?

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^@ . What is the value of horizontal component of earth's magnetic field at equator?

At a place, the horizontal component of earth's magnetic field is V and angle of dip is 60^(@) . What is te value of horizontal component of earth's magnetic field at equator ?

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

The strength of the earth's magnetic field is

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

The value of horizontal component of earth's magnetic field at a place is -.35xx10^(-4)T . If the angle of dip is 60^(@) , the value of vertical component of earth's magnetic field is about:

At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively