A short magnet `(M=4xx10^(-2))` lying in a horizontal plane with its north pole points `37^(@)` east of north. Find the net horizontal field a ta point of the magnet of 0.1m away from it `(B_(h)=11muT)(sin37^(@)=3//5,cos37^(@)=4//5)`
Text Solution
AI Generated Solution
To solve the problem of finding the net horizontal magnetic field at a point 0.1 m away from a short magnet, we will follow these steps:
### Step 1: Understand the Magnetic Field Due to a Short Magnet
The magnetic field \( B \) at a distance \( r \) from a short magnet can be calculated using the formula:
\[
B = \frac{\mu_0}{4\pi} \cdot \frac{2M}{r^3}
\]
where \( M \) is the magnetic moment of the magnet, and \( \mu_0 \) is the permeability of free space.
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