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A magnet performs 15 oscillations per mi...

A magnet performs 15 oscillations per minute in a horizontal plane, where angle of dip is `60^(@)` and earth is total field is 0.5G. At another place, where total field is 0.6G, the magnet performs 20 Oscillation per minutes. What is the angle of dip at this place.

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AI Generated Solution

To solve the problem, we will use the relationship between the oscillation frequency of a magnet and the magnetic field components. Here's the step-by-step solution: ### Step 1: Understand the Given Data - At the first location: - Number of oscillations per minute, \( n_1 = 15 \) oscillations/minute - Angle of dip, \( \phi_1 = 60^\circ \) - Total magnetic field, \( B_1 = 0.5 \, \text{G} \) ...
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