A thin rectangular magnet suspended freely has a period of oscillation equal to `T`. Now it is broken into two equal halves (each having half of the original length) and one piece is made to oscillate freely in the same field. If its period of oscillation is `T^(')`, then ratio `T^(')/T` is
Text Solution
AI Generated Solution
To solve the problem, we need to analyze the changes in the time period of oscillation when a rectangular magnet is cut in half. The time period of a magnet oscillating in a magnetic field can be expressed using the formula:
\[
T = 2\pi \sqrt{\frac{I}{mB}}
\]
where:
- \( T \) is the time period of oscillation,
...
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