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The couple acting on a magnet of length ...

The couple acting on a magnet of length 10cm and pole strength 15A-m, kept in a field of `B=2xx10^(-5)`, at an angle of `30^(@)` is

A

`1.5xx10^(-5)N-m`

B

`1.5xx10^(-3)N-m`

C

`1.5xx10^(-2)N-m`

D

`1.5xx10^(-6)N-m`

Text Solution

AI Generated Solution

To solve the problem of finding the couple acting on a magnet, we will follow these steps: ### Step 1: Identify the given quantities - Length of the magnet (2l) = 10 cm = 10 × 10^(-2) m = 0.1 m - Pole strength (m) = 15 A-m - Magnetic field (B) = 2 × 10^(-5) T - Angle (θ) = 30° ...
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