If a bar magnet moment M is freely suspended in a uniform magnetic field of strength field of strength B, then the work done in rotating the magent through an angle `theta` is

Options

A. `MB(1-sin theta)`
B. `MBsin theta`
C. `MB cos theta`
D. `MB(1-cos theta)`

Explanation

To find the work done in rotating a bar magnet with magnetic moment \( M \) through an angle \( \theta \) in a uniform magnetic field of strength \( B \), we can follow these steps:

### Step 1: Understand the Torque Acting on the Magnet
The torque \( \tau \) acting on a magnetic moment \( M \) in a magnetic field \( B \) is given by the formula:
\[ \tau = M \times B \sin(\phi) \]
where \( \phi \) is the angle between the magnetic moment and the magnetic field.
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