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What is the SI unit of permeability...

What is the SI unit of permeability

A

`Am^(-1)`

B

A-m

C

`"Henry m^(-1)`

D

No unit, it is a dimensionless number

Text Solution

AI Generated Solution

The correct Answer is:
To find the SI unit of permeability, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Permeability**: Permeability (denoted as μ) is a measure of how easily a magnetic field can penetrate a material. It is related to the inductance of a coil. 2. **Recall the Formula for Inductance**: The inductance \( L \) of a coil can be expressed in terms of permeability: \[ L = \frac{\mu n_1 n_2 A}{l} \] where: - \( L \) is the inductance, - \( n_1 \) and \( n_2 \) are the number of turns, - \( A \) is the cross-sectional area, - \( l \) is the length of the coil. 3. **Rearranging the Formula**: To isolate permeability \( \mu \), rearrange the formula: \[ \mu = \frac{L \cdot l}{n_1 n_2 A} \] 4. **Identify the Units**: - The unit of inductance \( L \) is Henry (H). - The unit of length \( l \) is meter (m). - The number of turns \( n_1 \) and \( n_2 \) are dimensionless (they have no units). - The unit of area \( A \) is square meter (m²). 5. **Substituting the Units**: Substitute the units into the rearranged formula: \[ \text{Units of } \mu = \frac{\text{Henry} \cdot \text{meter}}{\text{meter}^2} \] 6. **Simplifying the Units**: Simplify the expression: \[ \text{Units of } \mu = \frac{\text{H} \cdot \text{m}}{\text{m}^2} = \frac{\text{H}}{\text{m}} \] 7. **Conclusion**: Therefore, the SI unit of permeability is: \[ \text{Henry per meter (H/m)} \] ### Final Answer: The SI unit of permeability is **Henry per meter (H/m)**. ---
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